Bash add space to end of string. Here's an example of what I want: .


Bash add space to end of string If it's a shell script, you could actually ignore the existing quote and instead add the new part This gives me for example a string: 9. In bash command line, if I run "find . I'm writing a for loop in bash to run a command and I need to add a comma after one of my variables. -name 'abc*' ", it prints out a list of filenames like abc1 abc2 abc3 How can I pipe it with echo or other command, so that i get this output: abc1 ok ab Great, comprehensive answer. Bash has builtin string substitution. 5k 27 Redirection to a file is very usefull to append a string as a new line to a file, like echo "foo" &gt;&gt; file. For some reason I cannot get it to work completely. 00 Now I want to convert that string into: 9. wq saves and exits. Therefore using nocache may help (If disk is fast enough, or you are not reading the same data more than once). To answer the question as asked, you'd have to do sed 's/pattern. For this bit of code, I simply want to write the first line, and append a line break: echo "`date` User `whoami` started the script. What I hav I would like to add, that online regex checker shows that my regex is ok. You can use the following syntax to do so: sed 's/$/ city/g' cities. I have already achieved this through AWK but I would like to do it in SED something like this. Also note that your solution requires GNU sed (won't work on BSD/OSX, because the BSD sed implementation doesn't support escape sequence \n in the replacement string). sed '$!s/$/,/' file (The $ in the address refers to the last line while the $ in the regular expression in the substitution refers to the last character position on every line. contains the number of characters to add. 0m,5. I want to insert a space in the middle so that the string up 2 days, 12:32 becomes up 2 days, 12:32 I've been trying to do this using sed substitution. So if you know the string ends in a . The following removes any "ABC" string at the end, and its result can used in variable assignment, a command or whatever: ${String%ABC} You can also use a regex, not just a simple string match. str=$str$(printf '%*s' "$n" "") # pad with `n` spaces. Note that if I need to add a space right before the last character in that variable so that when echo'd it would look like 242 M. txt | xargs I have some text files as below. Each line has different numbers of spaces. The additional string is also stored after the original string. is the $ the last character of a line or the I want to add white space at the end of each line. The second snipped for example uses ^Word=[^\n]* to match from the beginning to the end of line. I know the sed syntax to add a line after another line in a file, which is sed -i '/LINE1/a LINE2' FILE This adds LINE2 after LINE1 in FILE correct? How do I add a line with a backslash at the end? For example, from This is I'm echoing some text in a bash script with a variable in it, and want to pad that variable so it will always have the appropriate ammount of spaces to the right to keep the rest of the text aligned. I am trying to do this in bash. When I move "," right next to I can't seem to do this without an extra space added. I have a file and I want to append the value in a unix variable at the end of each line using SED. -p: Loop over the input one line at a time, assigning it to $_ by default. I want to put each line within quotation marks, such as: abcdefg hijklmn opqrst convert to: "abcdefg" "hijklmn" "opqrst" How to do this in Bash shell script? I use the following command: xargs -I{lin} echo \"{lin}\" < your_filename The xargs take standard input (redirected from your file) and pass one line a time to {lin} placeholder, and then execute the command at next, in this First, it's usually better to be explicit about your intent. For example insert " hello world" to the next file hello world result: hello hello world world I am using this Repetition operators are modifiers. The goal of padding strings is to align text, organize data into In this comprehensive article, we will dig deep into the various methods and best practices around spacing and padding strings in Bash. {1,$n}") # limit length to `n` printf '|%s|\n' "${var}" . csv file, but the code below does not work: awk -F"," 'BEGIN How to split one string into multiple strings separated by at least one space in bash shell? 0 How to extract the first word that follows a string? 8 How to get the first part of the string in bash 4 Extract the two first words of a string 0 I have a line with spaces in the start for example " Hello world". I need to add some characters at the end of each line. I want to replace the spaces, tabs and the slash by only a This tutorial explains how to check if a string ends with a specific value using Bash, including several examples. I tried sed to remove "\r" with sed from that string and just (( )) with hope that math expression will truncate "\r" but still no success. You can do this by prepending hitting the space bar with a readline argument to indicate that you want it to happen 100 times, i. 4100, 51,19 CP0_1 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers If performance matters, you're doing a lot of unnecessary string concatenations when x becomes high. 0 20. I know there are several different ones open and answered but mine is a little different. If you want to retain the final newlines, put a stopper at the end and strip it away afterward. e. One small correction: strictly speaking, seq supports a subset of the format chars. ssh/authorized_keys' then the next line is $ ssh-add -K and walla! no more password prompt every time I need to remote onto that Hello I want my script to output the following: string1 string2 string1 string2 string2 string1 string2 string2 string2 string1 string2 string2 string2 string2 Etc. Making Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand OverflowAI GenAI features for Teams I would like to replace blank spaces/white spaces in a string with commas. You can see the xargs newline like this: echo -n "hey thiss " | xargs | hexdump you will Accumulate 'paragraphs' in the hold space. The newline character(s) at the end of the string will be stripped by the command substitution. 5. Also, the periods in the IP address are escaped with backslashes. rtf, it is not changed at all; var2 will contain an unmodified copy To get the last character you should just use -1 as the index since the negative indices count from the end of the string: echo "${str: -1}" The space after the colon (:) is REQUIRED. for about 20 times or so. g. Is it possible to either find and replace a line in a file OR append a string to the end if it is not there? I know I can use this to find and replace: sed -i -e "s/^SEARCH/LINE 1\\nLINE 2/" file I I need a Bash command that will convert a string to something that is escaped. /{ "aaData Adding answer to show example of stripping multiple characters including \r using tr and using sed. The length is 1-based and the array is 0-based indexed, so by passing the length in you are telling bash to assign your value to the slot after the last I am looking for BASH regex to pull the 'db' agruments from the below commands. 0m,9. Note that ARRAY is just a placeholder for an actual variable name. Then: sed "s/\$/$spaces/" In bash, you can use the In the following section, 6 easy methods have been mentioned to concatenate strings in bash which include using the literal value of the string, command substitution, and I would like to append ' eth0' to each of those output lines and then ideally for loop over the result to call a command with each line. var=$(echo "${str}"|grep -Eo "^. Note that I only use double quotes because simple quotes force bash to interpret literally the I need to format a mailing list, by adding a comma at the end of every line. 54 will change frequently so i need to store it in a variable and compare it with the value on the next ite I have a file (myfile. So don't use it in production code. 0600, 43. This question has been already asked, however I don't get the expected result with the suggested answer: sed '$!s/$/,/' # replace '$' (end of string marker) with 'Ipsum' # the `e` flag disables multi-line matching (treats all lines as one) $ echo "Lorem" | sd --flags e '$' 'Ipsum' Lorem Ipsum#no new line here You might observe that Ipsum appears on a new line, and the output is missing a \n . As you can see, there is a space in the middle of each filename. txt echo "bar" &gt;&gt; file. I tried the following: There is a space after the IP address in the if condition. And the script But the spaces are reduced to only one space. like: ${list} (before appending) => ' Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand x contains the number of characters to add. Here's an example of what I want: Length of string in bash UTF-8 string characters length versus string bytes length How to check if a string contains a substring in Bash String contain: POSIX compatibility, bash case independent, hints and remarks. This works just fine with bash 3. How do I ensure that the spaces aren't replaced? shell sh spaces Share Improve this question Follow edited Feb 19, 2013 at 14:27 Zero Piraeus 58. I need to add some words at the end of each line of a text file. This is the second line. awk '!/^#/ && !/source/{print $0,"","";next} 1' Input_file Explanation: simply looking for lines which are not starting with # and printing line with 2 spaces at last, next will skip going to 1(which is awksh way to print current lines) if any line does start with # then it will simply print it. I want to insert this line to a specific line in a file. 4. However the OS may be caching disk. 2. I would like to add a space character in all lines after all comma character. on the line that starts with USA_FORMAT=, replace the final " with /usr/END" (with the final quote at the end of the new string). I have output like: From: First Last From: First Last From: First Last I want to cut out the "From: " (essentially leaving the "Firs The cut command lines in your question specify colon-separated fields and that you want the output to consist only of field 7; since there is no 7th field in your input, the result I want to be able to prepend a string to the beginning of each text file in a folder. command to check if there are any words. Provide details and share your research! But avoid Asking for help, clarification, or responding to other answers. +)\n IIRC, the end-of-line - EOL end character(s) in Unix, Mac and Windows are all different. 54M" How would I extract the 19. And/or use the --unbuffered option of sed (so that just returns a single space and the rest of the string: blah blah How can I print the full string untouched? I want to use it for have a custom indent because \t is too much wide for my tastes. So, if I have the below two lines in someFile. If you really really want to use this method and are really worried about the globbing thing (and you really should), you can use set -f (which disables globbing altogether): How do I tell bash when you find the IP I tell you. If number of white space is fixed then I can use this command sed 's/$/ /g' for two spaces. go ro the lines end and add something or the other case When bash finds the comment #This is added automatically go down by 2 and than go to the end of the line and add Say I have the string "Memory Used: 19. But the only portable way to trim the length of the string is to use grep. An example testfile contains following content. Now, you want to insert 100 spaces. So I was wondering: How to add a newline at the end of a file to get rid of those messages? I have variable in my script called: VAR=/opt/sbin/test and I want to append a text for example 'text' at the end of the line with a space and then run the line as /opt/sbin/test text. */&\n/', otherwise you'll insert the newline right after the match instead of at the end of the line. So s~blabla\n is interpreted by sed as a single command. The idea is that the variable should NOT contain any spaces an You can use wc -w command to check if there are any words. pub | ssh [email protected] 'cat >> ~/. For example, given input of "aa bbccdd", you'd get output "aa Could you please try following. Using Parameter Expansion The parameter expansion is the process of manipulating the values of a variable. but it doesn't seems right. The following sed script has an address expression $! which matches lines which are not the last, and a substituton action s/$/,/ which adds a comma next to the end of line. How can I do in linux? J12_1xtc, 10, 10, 1,-10. 2). If there is a whitespace at the beginning it will add at the end, and if there is at the end will add at the beginning var string='This is test'; => or I'm writing a bash script to get some podcasts. 00 9. Visit I am trying to come up with a script to format forwards for apache, what I need to do is take a url, strip off the domain and then attach a "/" to the end of the line IF there is not one there alre I want to add the white space in the beginning and the end of a string if there isn't. bin in order to add the "IP=127. conf file. txt However, I need help adding space before and after these characters ```[]<>''' for example, nieStack Overflow for Teams Where developers & technologists share private knowledge with coworkers You can do this with pure bash and it works the way it does in languages like Python when you want an end point relative to the end of the string: $ x='this is my test string' $ echo ${x:1:-1} # Means "slice x beginning at index 1 to Often you may want to use Bash to add a suffix to the end of each line in a file. 0 The last part of the string will always be . Whether you need to connect Bash The %c format parameter transforms the string argument into its first character, so the full format string '%c ' prints the first character of the string followed by a space. Concatenating two strings of 256 spaces would be faster than prepending a space How do you define "special characters"? Is it exactly the set of chars in your question (!@#$%) or all punctuation chars or all non-alphabetic chars or something else?Or do you really just want a blank added between the \1 means the content of the first parentheses in word1 so it's the previous string, then you see a space and the variable you want to add. I have multiple wordpress installs, and I need to add a string to the end of every file called functions. " >> output. Add print $_ after each loop iteration. The order of the arguments is not guaranteed however. 3. ending each line with Carriage Return - CR (^M), while macs uses Line Feed - LF (^L My problem is that I read a file and got array of strings, but each my string has spaces in the end, I need to remove it. Assumptions: from a multi-line variable (qout) extract a line that contains a pattern (q)extract from the pattern (q) to the end of the line (to be captured in ${BASH_REMATCH[0]})A slight modification to the multi-line I'm having a bit of an issue cutting the output up from egrep. Probably issue is with grep. my target is to add the "IP=127. I am trying to add quotes to a string. space_variable=4; But if number of white Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand You're Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand OverflowAI GenAI features for Teams Hi I am having an array and want to add strings that contain spaces. Generally, when you have text that looks like a directory path, the basename and dirname commands can come in handy. php. You can also use xargs with echo for this: < file xargs -d "\n" -rI % echo '% | COUNTRY' This will make xargs take each line of file and pass it one at a time† to the specified echo command, replacing the % (or whatever character you choose) with the input line. txt) that contains these lines:foo bar qux In a bash script I'd like to add a value on the string resulting in foo 1000 bar 1000 qux 1000 I tried this but failed. – mklement0 This is a very elegant solution in terms of simplicity. Then we do not need any other command to get the desired output, as the default behaviour of awk is print $0 . Which prints: Note that rounded numbers are double width. I can figure out who o put the spaces pretty much anywhere else but at the end. would this be possible with tee? Add spaces between the characters of a string in Python # Add spaces to the end of a String in Python Use the str. Collecting Wisdom Skip to content Menu About Tutorials Bash Outlook PostgreSQL PowerShell Posted on April 14 After a decade developing Bash scripts for enterprise systems, I‘ve found string padding to be one of the most useful text formatting techniques. So change the regex. So the array's internals would end up looking i. To do I want to add a variable number of spaces to a string in C, and wanted to know if there is a standard way to do it, before I implement it by myself. I am currently trying to add the names of users, which are stored in variables, to the very proper, sir that is how I would carry it out. A newline is command delimeter inside sed. Until now I used some ugly ways to do it: Please assume that before I called any of the below functions, I took care to have enough memory allocated for the spaces I want to concatenate The question is a bit unclear - the example provided may mean you want to remove all #s, or remove the part after the last ". I'll show it with an example: File content some text at the beginning Result &lt; I would like to end up with below: ({ "aaData": append at the start of the file } appended at the end of the file) { "aaData": [alot of text] } What I have got so far: this does the appending at the start of the file $ sed '1s/. The ljust method takes the total I need to add the word "hallo" at the end of each filename before extension in the given directory. I've tried already: awk '{pri Here's another one with dc: { tr -cs 0-9 \\n echo '[pq]sq[z2>q+l+x]s+l+x' } <<\IN | dc <Summary failed="10" notExecuted="0" timeout="0" pass="18065" /> IN dc first reads in the whole infile - after tr has squeezed every sequence of not-number chars into a single \newline - and afterward it reads in a little echoed loop macro string which tells it to add all values on its stack each to the Using version control systems I get annoyed at the noise when the diff says No newline at end of file. You can have as many lines between "Wod"s, they should end up in hold space. When you get a blank/empty line, assume you have an accumulated paragraph. Thus, scripts like sed 's/\n//' file # to delete newlines from each line sed 's/\n/foo\n/' file # to add a word to the end of Giving the string: foo='Hello \ World! \ x we are friends here we are' Supose there are also tab characters mixed with spaces after or before the \ character. STR1=This is a string to STR1=This,is,a,string I have a shell script that I am executing in Cygwin (maybe this is the problem). My sed function looks like sed 's/,/, /' And I feel like that should work 1. log pattern space is entirely or partially deleted with 'd' or 'D', the newline is not added in such cases. When ERE syntax is enabled with the -r argument to sed, {1} doesn't mean "any one character", it means "exactly one of the preceding character" (which makes it a no-op, because when you don't specify otherwise, anything is expected to match exactly one of itself). bash shell shell-script Share edited 3 You pass in the length of the array as the index for the assignment. Alternatively, you can use sed or perl: Give a try to this: It looks for - and replace it with - (space hyphen) You are asking the shell to echo an I assigned a var like this: MYCUSTOMTAB=' ' But using it in echo both: echo $MYCUSTOMTAB"blah blah" or echo -e $MYCUSTOMTAB"blah blah" just returns a single filler='=====' string='foo' printf '%s\n' "$string${filler:${#string}}" Gives foo===== ${#string} is the length of the value $string, and ${filler:${#string}} is the substring of $filler from String padding refers to adding extra spaces or other characters to the beginning, middle, or end of text strings. As it stands, resolv. I have a file with text data. In this comprehensive article, we will dig deep into the various methods and best practices around if the string raches over 10 characters, cut the rest and add two dots & colon to the end ". Every time when I try them and then open the file in Notepad++ it shows what I want to I have strings which represent versions (always in the following format): 1. The captured identifiers are based on the (characters reading from left to right, so the regex (I've left off the \ escape characters and padded it a bit for clarity): Also, you have both bash and sh tagged. Problem I'm having is getting that extra string in the end to each line. How do I take a string, something simple like "Hello World!" and split it into its individual characters? Using the example above, I want an array with a single character put into each value. 0. The problem is that some of the podcast numbers are one digits while others are two/three digits, therefore I need to pad them to make them all 3 digits. How can I do this using bash on Linux? Skip to main content Stack Overflow About Products OverflowAI Stack Overflow for Teams Reach devs Replying to the comment: Here the grep solution is for (almost) Linux only, while the awk one is for every POSIX compliant OS (which means almost all OSs); so personally I would choose awk. ", or remove the part after the first "1", or even remove all charcters after character 13. -i. If the replacement string contains a slash, we can use a different delimiter for s instead: ed @ciembor: What do you mean, empty_space="${empty_space} "doesn't work? It appends a space to empty_space. If you want to change the file during the process, use -i option sed I'm writing a Bash script where I need to pass a string containing spaces to a function in my Bash script. 8. How can anyone include the quotes in the string to be inserted? I wanted to add the string "2. To make sure the OFS (output field separator) is a tab, you can do the following: I need to turn the string "125959" into "12:59:59". :" otherwise (if the string has less than 10 characters) fill the gap with spaces so they're alligned so on the example i provided i'd want something like this as output: Related: Add at the end of the line with sed I looked at this question and tried all methods in the top answer; none of them worked. Obviously, the string is the time so regular expressions aren't much good here. \s is a space and * mean 0 ore more occurence(s) & stands for the string matched in the left part of the substitution ^ as first character of a regex means start of string/line $ as last character of a regex means end of string/line This works for me sed '/^all:/ s/$/ anotherthing/' file The first part is a pattern to find and the second part is an ordinary sed's substitution using $ for the end of a line. This can also easily become a oneliner. But it does not work with grep. Swap the i have file in which i want to remove white space from the end of line test. The behavior of characters d and g differs subtly in that d interprets 0-prefixed numbers strings as octal numbers and converts them to decimal, whereas g treats them as decimals. Example: string123 example545 Output: string example Example: string123 example545 Output: string example Skip to main content what if i need to append a string to multiple specific files. Please @Birei, nice one thanx. . 189. bak' 's/$/:80/' foo. 00 5. See I am working on a bash script where ipset (an iptables extension) requires CIDR formatted entries to have "[single space]\\" appended to the end of each CIDR line for input into the set. Also, the way you wrote your RE, it would delete the entire line if it found the matching string. This approach will not work without the space. 50 string" I want to split that string with space as a delimiter and store the result in an array, so that the following: echo ${arr[0]} echo ${arr[1]} echo ${arr[2]} outputs I know that I can add space after or before a character using sed -i 's/char/char /g' fname. And illustrating using hexdump. to match from the beginning to the end of line. I'm trying to add a line of text to the middle of a text file in a bash script. - that is actually a This hard-codes the maximum key length to 20, but you can of course add code that iterates over the keys, computes the maximum, and then uses that to build the printf formatting string. the echo statements give no output and the file names are not cha So I was just starting learning bash scripting. With those you can shorten the solution of SLePort above somewhat. gz$//g'` Anyway, what this command does is remove the trailing . #!/usr/bin/bash MYVAL="1000" cat myfile. – lurker Add a specific string at the end of each line Ask Question Asked 4 years, 7 months ago Modified 4 years, 7 months ago It turns out it's slightly more efficient than myvar="${myvar// /}", but not safe regarding globs (*) that can appear in the string. The values string can vary in length and values, but always has two decimals. 2. txt is as following (there is white space at the end of line. translations are NOT a regex pattern match but rather, SET2 is CORRESPONDING to SET1. txt and want to add a date string 03/06/2012 with pipe- Hello|there|john Hello Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers sed does not use much memory. 7866, -1. as it expects. basename gives you the file's name without the leading path (lebowski in this case), and dirname gives you the directory name without the file (hello/my/name/is/ in this case). One potentially-useful aspect of this approach is that if the string doesn't end in . I tried: | sed -e 's/\(. These are two different shells, and would call for two different answers: The best-practice bash answer (assuming you really do want to add literal backslashes to your string) would use a How can I add a percentage symbol % to the end of the last line in a text file? I do not want the % to be on a new line, it must be at the end of the last line. No it does not assume that. Here's an example: echo "hello\world" | escape | someprog Where the escape command makes "hello\world" into "hello\\\world". - that is actually a really good idea, I would say go with it. Now I'm searching for a way in bash Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers Consider you have a shell variable foo, whose value is echo ${foo} # Output: elementA elementB elementC Now I would like to add same prefix __PREFIX__ and suffix __SUFFIX__ to the elements, so th Planned maintenance impacting Stack Overflow and all Stack Exchange sites is scheduled for Wednesday, October 23, 2024, 9:00 PM-10:00 PM EDT (Thursday, October 24, 1:00 UTC - Thursday, October 24, 2:00 Remember that sed uses the slash by default to demark the search string, which uses two of your slashes. How to add text at the end of each line in unix 7 How can I add a newline after match is found 0 Remove the newline character in awk 15 How to print out a newline character in a string in Awk 0 Create a new line for my last 0 0 I've tried all solutions that I found, but nothing seems to work as it should. How can I do this? Right now I can delete all spaces from Im trying to add 5 blank spaces to the end of each line in a file in a sed script. How can I do this with a Bash script? Example: add the word done at the end of each line: line1 abcdefg done line2 abcdefg done line3 abcdeft done So far I've been able to find out how to add a line at the beginning of a file but that's not exactly what I want. txt However -i option is non-standard Unix extension and may not be available on all operating systems. result = my_str. I encountered a question in a book. This is the third line. How can this be done? the following example code shows what I want to do: #!/bin/bash # works on BASH versions &gt;4 ShowArray I'm going to answer by only inserting spaces as required so a space appears at least after every 4 characters on a line; not sure which way you want to handle this case. The tr translations are NOT a regex pattern match but rather, SET2 is CORRESPONDING to SET1. So ignore the second decimal and add m,. Well, that's the goal. I've tried sed but it looks like from what I can find that only spaces=$(printf "%*s" "$space_variable" "") That will return the empty string padded with spaces to a field N characters wide. 168. I have this file: Line1 asd asd asd \ asd asd asd \ Line2 asd asd as The bash built-in read supports backslash-continued lines when you don't use -r (Other then when you need exactly this support you always should use -r). I've While all of these answers are technically correct that appending to a file with >> is generally the way to go, note that if you use this in a loop when for example parsing/processing a file and append each line to the resulting file, this might be much slower then you would expect. Stack Exchange Network Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. 54 from it? The 19. Like this: stackoverflow =&gt; 'stackoverflow' And then append this string to another variable separated by a 'comma'. The only problem with xargs is that it will introduce a newline, if you want to keep the newline off I would recommend sed 's/ *$//' as an alternative. If you'd like to add text at the end of each line in-place (in the same file), you can use -i parameter, for example: sed -i'. In terms of overhead I want to add a specific string at the beginning of each line in a file. I finally understood how the tr command achieves a space after the 1st string output. I've tried wrapping each name in quotes, and escaping the space with a backslash, neither of which works. Keep accumulating as long as the input line contains any non-space character(s). In POSIX-compliant shells, you can write I have a variable which contains a space-delimited string: line="1 1. You can handle outputting the first part of the heading in the second rule, saving all fields in the array a[], and then the second rule will output the needed elements of a[] and the current fields in the format you specify. I h String, say 133, with "\r" at the end, so it is "133\r". How are you checking the value later? Presumably by printing it to your screen? Are you quoting it then? That. Share Improve this answer It can all be done in awk with two rules. In my case I had found that a command ending with awk print of the last item |awk '{print $2}' in the line In the here doc the first line is the original string which is declared before the heredoc starts. I can't seem to do this without an extra space added. For example: #!/bin/bash myFunction { echo $1 echo $2 echo $3 } myFunction "firstString" "second string with spaces bash can do this internally. For example I need to add a space right before the last character in that variable so that when echo'd it would look like 242 M I've tried sed but it looks like from what I can find that only works with reading from a file and I haven't been able to get this to work modifying a variable. 1" -because its binary file I need advice how we can to add I want to remove digits from end of a string. In terms of how the capture groups work, you can use parentheses to store the text that matches a pattern for later use in the replacement. Otherwise, the regex could match 192. Specifically I'm trying add a nameserver to my /etc/resolv. one more thing. gz extension from the filename, which isn't what you're looking for according to your question. sed is a Unix utility so it uses the Unix convention, i. rtf that you want to remove, you can just use var2=${var%. 20 etc. The solution also nicely extends to appending a suffix, which I needed Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. that printf supports (and that subsets includes g, but not d). With $2="chr"$2 we add chr to the 2nd field. Integer, which I want to add to the number from the string above. 0 1. $ cat testfile This is the first line. 0 456874. I am taking baby steps at learning bash and I am developing a piece of code which takes an input and checks if it contains any spaces. ath-miRf10005-akr ath-miRf10018-akr ath-miRf10019-akr ath-miRf10020-akr ath-miRf10023-akr ath Bash (and likely other shells) gobble all the trailing newlines after command substitution, so you need to end the printf string with a non-newline character and delete it afterwards. Then, someprog can use "hello\\world" as it expects. 1. 48 (OS X 10. ljust(6, ' '). ljust() method to add spaces to the end of a string, e. conf looks like this: # Using ed: ed infile <<'EOE' ,s/^/prefix/ wq EOE This substitutes, for each line (,), the beginning of the line (^) with prefix. Number of white space is in variable. 0m. 0" (inluding quotes) in the second column of a . txt This particular example will add the suffix ” city” to the end of each line in the text. ssh/id_rsa. plus if you're not starting with a file then >> will touch it with any extenion you give or none at all, for example one my favorite lines of code: $ cat ~/. Imagine you wanted 512 spaces. How do I split To answer the first line of your question which asks to "remove the last n characters from a string", you can use the substring extraction feature in Bash: A="123456" echo ${A:0:-2} # remove last 2 chars 1234 However, based on your Append different number of spaces at the end of a string 0 Bash, put a space after a specific coma 0 Sed replace spaces and a character before end of line 2 How to append space before match pattern in bash 1 sed: replace a 0 0 I have been working on a bash script that is supposed to loop through a list of users you are supposed to have and a list of users on the system. When I try to access the array elements, it continues to In another question I just came across the markers for beginning (\<) and end (\>) of words. txt Result: foo bar But is it also possible to redir Use $ to match the end of the line: FILE=`echo ${FILE} | sed 's/. bak: Edit input files in-place (overwrite the input file). Even if your array indices are not sequential, appending with += will simply assign to the highest index + 1. rtf}. Thanks! Thanks for contributing an answer to Stack Overflow! The Perl one-liner uses these command line flags:-e: Tells Perl to look for code in-line, instead of in a file. , you manually enter what would look like this as a readline Alt In sed commands end with a newline. 1" after each line that created by tee (the IP address is example) remark: we can't modify the script. but my code produces no output. ryiolb gvrx argkwdnw tgi wptx tlfs fljd uxvmdr atggdv xyfg